Предмет: Алгебра, автор: owl58

Даю 35 баллов!!!
Только (в)

Приложения:

Ответы

Автор ответа: AntVa

1

$(\frac{2a^2-a}{a^2-a+1}-2\frac{a^2-a+1}{a^2-a+1}):(\frac{1}{a+1}-\frac{a-1}{a^2-a+1})=(\frac{2a^2-a-2a^2+2a-2}{a^2-a+1}):(\frac{(a^2-a+1)}{(a+1)(a^2-a+1)}-\frac{a^2-1}{(a+1)(a^2-a+1)})=\frac{a-2}{a^2-a+1}*\frac{(a+1)(a^2-a+1)}{a^2-a+1-a^2+1}=\frac{(a-2)(a+1)}{-(a-2)}=-a-1$

owl58: Спасибо большое!

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