Question

Решите под номером 4, под буквами Б и В...

Answer 1

$\frac{1}{3}(x-6)+2 \frac{2}{3}+4( \frac{1}{5}+x)=0\\\frac{1}{3}x-2+ 2\frac{2}{3}+ \frac{4}{5}+4x=0\\\frac{1}{3}x+ \frac{2}{3}+ \frac{4}{5}+4x=0\\4\frac{1}{3}x=- \frac{22}{15}\\\frac{13}{3}x=- \frac{22}{15}\\x=-\frac{22}{15}: \frac{13}{3} \\x=-\frac{22}{65} \\5x+34-3(x-2)=x-7\\5x+34-3x+6=x-7\\2x-x=-7-40\\x=-47$