Question

cos x = 1/3;sin x-?
помогите

Answer 1

$|\sin x|=\sqrt{\sin^2 x}=\sqrt{1-\cos^2 x}=\sqrt{1-\frac{1}{9}}=\sqrt{\frac{8}{9}}=\frac{2\sqrt 2}{3}\\\\\sin x = \pm \frac{2\sqrt 2}{3}$