Question

решите 6 пример пожалуйста

Answer 1

Especially for you...

Answer 2

$(\frac{a}{a-4} -\frac{a}{a+4} -\frac{a^2+16}{16-a^2}) /\frac{4a+a^2}{(4-a)^2} =\\ \\ \frac{a^2+4a-a^2+4a+a^2+16}{(a+4)(a-4)} *\frac{(a-4)(a-4)}{a(a+4)} =\\ \\ \frac{(a^2+8a+16)(a-4)}{a(a+4)(a+4)} =\frac{a-4}{a}$