Question

найти значение многочлена 2y^3-3y^2+4y-6 при y=1, y=0, y=-5

Answer 1

у=1
$2 \times 1 - 3 \times 1 + 4 \times 1 - 6 = 2 - 3 + 4 - 6 = - 3$
у=0
$2 \times 0 - 3 \times 0 + 4 \times 0 - 6 = - 6$
у=-5
$2 \times ( { - 5}^{3} ) + - 3 \times ( { - 5}^{2} ) + 4 \times ( - 5) - 6 = 2 \times - 125 + 3 \times 25 - 20 = - 250 + 75 - 20 = - 195$