Question

(y+2)²-(y+2)-12=0


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Answer 1

$(y + 2) {}^{2} - (y + 2) - 12 = 0 \\ {y}^{2} + 4y + 4 - y - 2 - 12 = 0 \\ {y}^{2} + 3y - 10 = 0 \\ d = 9 - 4 \times 1 \times ( - 10) = 9 + 40 = 49 > 0. \: 7. \\ x1 = \frac{( - 3) + 7}{2} = \frac{4}{2} = 2. \\ x2 = \frac{( - 3) - 7}{2} = \frac{ - 10}{2} = - 5.$
Ответ : х = -5 ; 2.

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