Question

Найти производную функции :
1) f(x)=1/4x⁴-8x²+3
2)f(x)=x¹⁰-80x

Answer 1

$(\frac{1}{4} x^{4} -8x^{2}+3)'\\4*\frac{1}{4} x^{3}-8*2x\\x^{3}-16x\\\\(x^{10} -80x)'\\10x^{9}-80$