Question

там где надо сокращение напишите рядом пж

Answer 1

а)$\frac{5}{8} +\frac{1}{4}+\frac{7}{12} =$                                   $\frac{15+6+14}{24}$=$\frac{35}{24}$

б)=$\frac{10-32+1}{12} = -\frac{21}{12} = -\frac{7}{4}$

в)=$\frac{18+33-4}{42} =\frac{47}{42}$

г) =$\frac{63+45-35}{315} = \frac{73}{315}$

д) = $1) \frac{29+12}{72} =\frac{41}{72} 2) \frac{13}{18} -\frac{1}{24} -\frac{41}{72} = \frac{52-3-41}{72} =\frac{8}{72} = \frac{1}{9}$

e)$1)\frac{7}{8} -\frac{4}{5} =\frac{35-32}{40} =\frac{3}{40} 2) \frac{1}{20} + \frac{1}{4} =\frac{1+5}{20} =\frac{6}{20} = \frac{3}{10} 3) \frac{3}{40} +\frac{3}{10} +\frac{1}{2} =\frac{3+12+20}{40} =\frac{35}{40} =\frac{7}{8}$