Question

сократить дробь 4y^2+y+5/4y-4

Answer 1

4y^2+y-5 / 4y-4

4y^2 + y - 5 = 0

D = b^2 - 4ac = 1^2 - 4 * 4 * ( - 5) = 1 + 80 = 81

y1 = (- 1 - √81) / 2 * 4 = (- 1 - 9) / 8 = - 10 / 8 = - 5/4

y2 = (- 1 + √81) / 2 * 4 = (- 1 + 9) / 8 = 8 / 8 = 1

(y + 5/4) (y - 1)/(y - 1) * 4 = (y + 5/4)/4 = y/4 + 5/16