Question

Решите уравнения: 6*(х-3)-2(х+2)=10, 5(х-1)-4(х-3)=-20

Answer 1

6(x-3)-2(x+2)=10
6x-18-2x-4=10
4x-22=10
4x=10+22
4x=32
x=32÷4
x=8

5(x-1)-4(x-3)=-20
5x-5-4x+12=-20
x+7=-20
x=-20-7
x=-27

Answer 2

1) 6x-18-2x-4=10;
4x-22=10;
4x=32;
x=8;

2) 5x-5-4x+12=-20;
5x-4x=-20+5-12;
x=-27