Question

Алгебра 11 класс, производные, СРОЧНО!!!

Answer 1

$( \sin( \frac{\pi}{6} - \frac{x}{5} ) - \cos( - 3x + 4))^{l} = (\sin( \frac{\pi}{6} - \frac{x}{5} )) ^{l} - (\cos( - 3x + 4))^{l} = \cos( \frac{\pi}{6} - \frac{x}{5}) \times ( \frac{\pi}{6} - \frac{x}{5}) ^{l} - ( - \sin(- 3x + 4) \times (- 3x + 4)^{l} = - \frac{\cos( \frac{\pi}{6} - \frac{x}{5})}{5} - 3\sin(- 3x + 4)$
$( \sqrt{ {x}^{2} + 6x - 3} )^{l} = \frac{1}{2\sqrt{ {x}^{2} + 6x - 3}} ( {{x}^{2} + 6x - 3})^{l} = \frac{2x + 6}{2\sqrt{ {x}^{2} + 6x - 3}} = \frac{x + 3}{\sqrt{ {x}^{2} + 6x - 3} }$