Question

Решите уравнение
а (x-4)/6-(2x+1)/3=3
б (2x-1)/15-(2+x)/5+(3x-2)/5=1-x

Answer 1

а) (х-4)/6-(2х+1)/3=3 |*6
(Х-4)-2*(2х+1)=18
-3х-6=18
-3х=24
Х=-8

Answer 2

1|

$\frac{x-4}{6}-\frac{2x+1}{3}=3\\\\\frac{6*(x-4)}{6}-\frac{6*(2x+1)}{3}=6*3\\\\1*(x-4)-2*(2x+1)=18\\\\x-4-4x-2=18\\\\-3x=18+6\\\\-3x=24\\\\x=24:(-3)\\\\x=-8$

2)

$\frac{2x-1}{15}-\frac{2+x}{5}+\frac{3x-2}{5}=1-x\\\\\frac{15*(2x-1)}{15}-\frac{15*(2+x)}{5}+\frac{15*(3x-2)}{5}=15*(1-x)\\\\1*(2x-1)-3*(2+x)+3*(3x-2)=15-15x\\\\2x-1-6-3x+9x-6=15-15x\\\\8x-13=15-15x\\\\8x+15x=13+15\\\\23x=28\\\\x=28:23\\\\x=1\frac{5}{23}$