Question

3x^2-13x-10=(3x+2)(x-a) найдите а

Answer 1

$3x^2-13x-10=3(x+\frac{2}{3} )(x-5)=(3x+2)(x-5)\\ \\ D=13^2+4*3*10=169+120=289=17^2\\ \\ x_{1} =(13-17)/6=-\frac{2}{3} \\ \\ x_{2} =(13+17)/6=5 \\ \\ otvet:a=5$