Question

Помогите по алгебре, пж

Answer 1

$\frac{(m+1)^{2}} {169-169m^{3}}: \frac{1-m^{2}} {(13m-13)^{2}}=  \frac{(m+1)(m+1)(13m-13)^{2}}{(169-169m^{3})(1-m^{2})}=\\ =\frac{13*13(m+1)(m+1)(m-1)(m-1)}{169(1-m)(1+m+m^{2})(1-m)(1+m)}=\\ =\frac{m+1}{1+m+m^{2}}$