Question

lgx=1/3lga+2lgb-3lga

Answer 1

$lgx=\frac{1}{3}lga+2lgb-3lga\\lgx=lga^{\frac{1}{3}} +lgb^{2}-lga^{3}\\lgx=lg\frac{a^\frac{1}{3}*b^{2}}{a^{3}}\\lgx=lg\frac{b^{2}} {a^{2\frac{2}{3}} }\\lgx=lg\frac{b^{2}} {\sqrt[3]{a^{8}} }\\lgx=\frac{b^{2}} {a^{2}\sqrt[3]{a^{2}} } \\x=\frac{b^{2}} {a^{2}\sqrt[3]{a^{2}} }$