Question

Решите уравнение
16x в квадрате - (4x-1) (4x-3) =19

Answer 1

${16x}^{2} - (4x - 1)(4x + 3) = 19 \\ {16x}^{2} - 16x {}^{2} - 12x + 4x + 3 = 19 \\ - 8x + 3 = 19 \\ - 8x = 19 - 3 \\ - 8x = 16 \\ x = 16 \div ( - 8) \\ x = - 2.$
Ответ : х = -2.

Удачи))))

Answer 2

16x²- (4x-1) (4x-3) =19
16x²-(16x²+12x-4x-3)=19
16x²-(16x²+8x-3)=19
16x²-16x²-8x+3=19
-8x+3=19
-8x=19-3
-8x=16
x=-2