Question

$\frac{4x-3}{2} - \frac{5-2x}{3} = \frac{3x-4}{3}$

Answer 1

$6 \times \frac{4x - 3}{2} - 6 \times \frac{5 - 2x}{3} = 6 \times \frac{3x - 4}{3} \\ \\ 3(4x - 3) - 2(5 - 2x) = 2(3x - 4) \\ 12x - 9 - 10 + 4x = 6x - 8 \\ 16x -19 = 6x - 8 \\ 16x - 6x = - 8 + 19 \\ 10x = 11 \div (10) \\ x = 1.1$