Question

решите пж номер 2 , 6 , 7

Answer 1

2) $\frac{n^2-2n}  {2n-4} = \frac{n(n-2)}{2(n-2)} =\frac{n}{y2}$

6) $\frac{b^8} {b^5} =b^3$ если b= -0.5

$-0.5^{3} =-(\frac{1}{2})^{3}= - \frac{1}{8}$

7) $5,7^{2} +4,6*5,7+2,3^{2} = (\frac{57}{10} )^{2} +26,22+(\frac{23}{10} )^{2} =\frac{3249}{100} + \frac{1311}{50} +\frac{529}{100} =\frac{3249+2622+529}{100} =\frac{6400}{100} =64$