Question

Найдите нули функции у=3х^2-12х+2

Answer 1

$y = 3 {x}^{2} - 12x + 2 \\ 3 {x}^{2} - 12x + 2 = 0 \\ d = {b}^{2} - 4ac = {12}^{2} - 4 \times 3 \times 2 = 144 - 24 = 120 \\ x1= \frac{12 +2 \sqrt{30} }{6} = 2 + \frac{1}{3} \sqrt{30} \\ x2 = \frac{12 - 2 \sqrt{30} }{6} = 2 - \frac{1}{3} \sqrt{30}$