Question

$log_6{90} - log_6{2,5} + log_16 log_4{16}$

Answer 1

$log_{6}(90) - log_{6}(2.5) + log_{16}( log_{4}(16) ) = \\ = log_{6}( \frac{90}{2.5} ) + log_{16 }(2) = log_{6}(36) + log_{16}(2) = \\ = 2 + \frac{1}{4} = 2 + 0.25 = 2.25$


ОТВЕТ: 2,25