Question

$log_6{234}- log_6{6,5} +log_16 log_3{9}$

Answer 1

$log_{6}(234) - log_{6}(6.5) + log_{16}( log_{3}(9) ) = \\ = log_{6}( \frac{234}{6.5} ) + log_{16}(2) = log_{6}(36) + log_{16}(2) = \\ = 2 + \frac{1}{4} = 2 + 0.25 = 2.25$


ОТВЕТ: 2,25

Answer 2

log6(234/6,5)+log2^4 (log3(3^2))=log6(36)+log2^4(2)=log6 (6^2)+1/4=2+1/4=9/4=2 1/4=2,25