Question

Ребят, выручайте плиз! Помогите со 2 заданием!

Answer 1

$\frac{b + 3}{9b - 27} - \frac{b - 1}{ {b}^{2} - 3b} = \frac{b + 3}{9(b - 3)} - \frac{b - 1}{b(b - 3)} = \frac{ {b}^{2} + 3b - 9b + 9}{9b(b - 3)} = \frac{(b - 3)^{2} }{9b(b - 3)} = \frac{b - 3}{9b}$

Answer 2

$\frac{b+3}{9b-27} -\frac{b-1}{b^{2}-3b} = \frac{b+3}{9(b-3)}- \frac{b-1}{b(b-3)}= \frac{b^{2}+3b-9b+9} {9b(b-3)}= \frac{b^{2}-6b+9} {9b(b-3)}=\frac{(b-3)^{2}} {9b(b-3)}= \frac{b-3}{9b}$