Question

Z1=-6+i
Z2=3-2i
Найти:
Z1*Z2, Z1/Z2

Answer 1

$Z_1*Z_2=(-6+i)(3-2i)= -18+12i+3i+2=-16+15i\\ \frac{Z_1}{Z_2}=\frac{-6+i}{3-2i}=\frac{(-6+i)(3+2i)}{(3-2i)(3+2i)}=\frac{-18-12i+3i-2}{9+4}=\frac{-20-9i}{13}=-\frac{20}{13}-\frac{9}{13}i$