Question

решите неравенство (1/3)^2-4x<1/27

Answer 1

$(\frac{1}{3})^{2}-4x<\frac{1}{27}\\\frac{1}{9}-4x<\frac{1}{27}\\-4x<\frac{1}{27}-\frac{1}{9}\\-4x<-\frac{2}{27}\\x>\frac{1}{54}\\x\in(\frac{1}{54};+\infty)$