Question

помогите решить
2^(1-3x)=16

Answer 1

$2^{1-3x} = 16$

$2^{1-3x} =  2^{4}$

$1-3x = 4$

$-3x=3\\\\x=3:-3=-1$

Проверка:

$2^{1-(-3)}= 2^{4} = 16$