Question

Решите систему {у=х²
{ х=у²

Answer 1

$\left \{ {{y=x^2} \atop {x=y^2}} \right. \\ \\ x=y^2=(x^2)^2=x^{4}\\ \\ x^{4}-x=0\\ \\x(x^3-1)=0 \\ \\ x(x-1)([tex]x_{1} =0;y_{1} =0\\ \\ x_{2} =1;y_{2} =1\\ \\ x^2+x+1\neq 0,t.k.D<0\\ \\ otvet:(0;0)(1;1)$)=0\\ \\[/tex]