Предмет: Алгебра, автор: arisha11102

помогите решить
log_√3 ³√81
log_¹/5 25
log_2 lg 10000

Ответы

Автор ответа: sangers

1

log(√3) ∛81=log(3¹/²) ∛3⁴=2*log₃ 3⁴/³=(2*4/3)log₃3=8/3.

log₁/₅25=log(5⁻¹) 5²=-log₅5²=-2*log₅5=-2.

log₂(lg10000)=log₂(lg10⁴)=log₂(4*lg10)=log₂4=log₂2²=2*log₂2=2.

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