Question

Помогите п о ж а л у й с т а

Answer 1

$\frac{3-2a}{2a}- \frac{1-a^{2}} {a^{2}} =\frac{3a-2a^{2}-2+2a^{2}}{2a^{2}}= \frac{3a-2}{2a^{2}}\\\frac{1}{3x+y}- \frac{1}{3x-y} =\frac{3x-y-3x-y}{(3x-y)(3x+y)}= \frac{-2y}{9x^{2}-y^{2}}= \frac{2y}{y^{2}-9x^{2}}$