Question

Сделайте пожалуйста)) Буду благодарна)

Answer 1

$\frac{14 {x}^{4}y }{49 {x}^{3} {y}^{2} } = \frac{2x}{7y}$

$\frac{5x}{ {x}^{2} + 3x } = \frac{5x}{x(x + 3)} = \frac{5}{x + 3}$

$\frac{ {x}^{2} - {y}^{2} }{2x - 2y} = \frac{(x - y)(x + y)}{2(x - y)} = \frac{x + y}{2}$

$\frac{ {x}^{2} - 16 }{ {x}^{2} - 8x + 16 } = \frac{(x - 4)(x + 4)}{(x - 4) {}^{2} } = \frac{x + 4}{x - 4}$