Question

Решите, пожалуйста.

Answer 1

$\left \{ {{2x-6}\leq0\atop {x^2+7x+6>0}} \right. \\ \\ \left \{ {{2(x-3)}\leq0\atop {x^2+x+6x+6>0}} \right. \\ \\ \left \{ {{2(x-3)}\leq0  \atop {(x+1)(x+6)>0}} \right. \\ \\ \left \{ {{x}\leq 3 \atop {x\in(-oo;-6)U(-1;+oo)}} \right. \\ \\ otvet:x\in(-oo;-6)U(-1;3]$