Question

хелп!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$\displaystyle\tt x^{2} +\frac{16}{x^2} =41; \ \ \ x \neq0 \\\\\\\ x^{2} +\left(\frac{4}{x}\right)^2 =41\\\\\\ x^{2} +\left(\frac{4}{x}\right)^2 +2\cdot x\cdot\frac{4}{x}=41 + 2\cdot x\cdot\frac{4}{x} \\\\\\ \left(x+\frac{4}{x}\right)^2=41+8\\\\\\ \left(x+\frac{4}{x}\right)^2=49\\\\\\ x+\frac{4}{x}=б7$

Ответ: ±7.