Question

Помогите пожалуйста ( задание во вложении)

Answer 1

решение на фото..............................

Answer 2

$\frac{6x {}^{2} {y}^{3} }{18 {x}^{3} y} = \frac{ {y}^{2} }{3x}$
$\frac{ {x}^{2} - 2xy + {y}^{2} }{3x(x - y) {}^{2} } = \frac{(x - y) {}^{2} }{3x(x - y) {}^{2} }= \frac{1}{3x }$
$\frac{{x}^{2} - {y}^{2} }{x(x + y)} = \frac{(x - y)(x + y)}{x(x + y)} = \frac{x - y}{x}$