Question

Решите систему уравнений методом алгебраического сложения.
x^2-3y^2=22
x^2+3y^2=28

Answer 1

$\left \{ {{}x^{2}-3 y^{2}=22  \atop x^{2}+3 y^{2}=28 } \right. \left \{ {{}2x^{2}=50  \atop x^{2}+3 y^{2}=28 } \right. \\\left \{ {{}x^{2}=25  \atop x^{2}+3 y^{2}=28 } \right. \\\left \{ {{}x}=+-5  \atop x^{2}+3 y^{2}=28 } \right. \\\left \{ {{}x}=+-5  \atop 5^{2}+3 y^{2}=28 } \right. \\\\\left \{ {{}x}=+-5  \atop 3 y^{2}=3 } \right. \\\\\left \{ {{}x}=+-5  \atop  y=+-1 } \right.$