Question

$\frac{x(x + 6)}{2} - \frac{x(x + 14)}{3} - \frac{ {x}^{2} + 1 }{6} = 0$
помогите решить задачу

Answer 1

$\frac{x(x + 6)}{2} - \frac{x(x + 14)}{3} - \frac{ {x}^{2} + 1 }{6} = 0 \\ 3 {x}^{2} + 18x - 2 {x}^{2} - 28x - {x}^{2} - 1 = 0 \\ - 10x = 1 \\ x = - \frac{1}{10} = - 0.1$