Question

Помогите пж срочно надо 1.163

Answer 1

$x^2+2x+3=x^2+2x+1+2=(x+1)^2+2=(\sqrt{3} -1+1)^2+2=3+2=5\\ \\ x^2-6x+3=x^2-6x+9-6=(x-3)^2-6=(3-\sqrt{7} -3)^2-6=7-6=1$