Question

Найдите производную
f(x)=(3- (4/x^4))(x^2+1)

Answer 1

$f(x)=(3-\frac{4}{x^4} )(x^2+1)\\ \\ f'(x)=(3-\frac{4}{x^4} )'(x^2+1)+(3-\frac{4}{x^4} )(x^2+1)'=\\ \\ \frac{16}{x^5} (x^2+1)+2x(3-\frac{4}{x^4} )=\\ \\ \frac{16}{x^3} +\frac{16}{x^5} +6x-\frac{8}{x^3} =\frac{16}{x^5} +\frac{8}{x^3} +6x$