Question

привести к рациональному виду числитель дроби

Answer 1

$\frac{\sqrt{2}}{2}\times1=\frac{\sqrt{2}}{2}\times\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}\times\sqrt{2}}{2\times\sqrt{2}}=\frac{2}{2\sqrt{2}}=\frac{1}{\sqrt{2}}$

$\frac{\sqrt{6}}{3}\times1=\frac{\sqrt{6}}{3}\times\frac{\sqrt{6}}{\sqrt{6}}=\frac{\sqrt{6}\times\sqrt{6}}{3\times\sqrt{6}}=\frac{6}{3\sqrt{6}}=\frac{2}{\sqrt{6}}$

$\frac{\sqrt{5}}{5}\times1=\frac{\sqrt{5}}{5}\times\frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{5}\times\sqrt{5}}{5\times\sqrt{5}}=\frac{5}{5\sqrt{5}}=\frac{1}{\sqrt{5}}$

$\frac{\sqrt{10}}{5}\times1=\frac{\sqrt{10}}{5}\times\frac{\sqrt{10}}{\sqrt{10}}=\frac{\sqrt{10}\times\sqrt{10}}{5\times\sqrt{10}}=\frac{10}{5\sqrt{10}}=\frac{2}{\sqrt{10}}$