Question

решите задания по алгебре

Answer 1

1)
$3 \times \sqrt[4]{16} - 4 \times \sqrt[3]{27} = 3 \times 2 - 4 \times 3 = 6 - 12 = 6$
2)
$14 - \sqrt[4]{196} \times {14}^{ \frac{1}{2} } = 14 - \sqrt[4]{ {14}^{2} } \times \sqrt{14} = 14 - \sqrt{14} \times \sqrt{14} = 14 - 14 = 0$
3)
$6 \times {49}^{ \frac{1}{2} } - {64}^{ \frac{1}{3} } = 6 \times \sqrt{49} - \sqrt[3]{64} = 6 \times 7 - 4 = 38$
4)

$\sqrt{10 - \sqrt{96} } \times \sqrt{10 + \sqrt{96} } = \sqrt{ {10}^{2} - { \sqrt{96} }^{2} } = \sqrt{100 - 96} = \sqrt{4} = 2$
5)
$4 \times \sqrt[3]{25} \times 2 \times \sqrt[3]{40} = 8 \times \sqrt[3]{25 \times 40} = 8 \times \sqrt[3]{1000} = 8 \times 10 = 80$
6)
$4 \times \sqrt[3 ]{ \frac{540}{20} } = 4 \times \sqrt[3]{27} = 4 \times 3 = 12$