Question

3sin0°+cos60°+tg30°-sin90°

Answer 1

$3Sin0^{0}+Cos60^{0}+tg30^{0}-Sin90^{0}=3*0+\frac{1}{2}+\frac{\sqrt{3} }{3}-1=\frac{3+2\sqrt{3} }{6}-1$$=\frac{3-2\sqrt{3}-6 }{6}=-\frac{2\sqrt{3}+3 }{6}$