Question

решите плес. дам 30 баллов

Answer 1

$\frac{1}{x^{3}-8}-\frac{1}{x-2}+\frac{x+2}{x^{2} +2x+4}=\frac{1-(x^{2}+2x+4)+(x+2)(x-2)}{x^{3}-8}$$=\frac{1-x^{2}-2x-4+x^{2}-4}{x^{3}-8 }=\frac{-2x-7}{x^{3}-8 }=\frac{2x+7}{8-x^{3}}$