Question

3x^ - 11x + 6 < 0 решите неравенство

Answer 1

$3x^{2} - 11x + 6 < 0 \\ d = 121 - 4 \times 3 \times 6 = 49 \\ \sqrt{d} = 7 \\ x1 = \frac{ 11 + 7}{2 \times 3} = 3 \\ x2 = \frac{2}{3} \\ (( \frac{2}{3} )(3))$