Question

80,3+3/8ув 2 степени

Answer 1

$\frac{80.3 + 3}{8yb {}^{2} } \\ \\ \frac{83.3}{8b {}^{2}y } \\ \\ \frac{833}{10 \div 8b {}^{2}y } \\ \\ \frac{833}{80b {}^{2} y}$