Question

Помогите пожалуйста!!!!!

Answer 1

В 10 не уверена... Так что оставлю профессионалам

Answer 2

1) (3-2i)+(5+3i)=8+i;

2) (1+3i)(-7+2i)=-7-21i+2i+3i*2i=-7-19i+6i²=-7-19i+6*(-1)=-7-19i-6=-13-19i;

3) (1+2i)-(3-i)=1+2i-3+i=-2+3i;

4) (2-i)²=4-4i+i²=4-4i-1=3-4i;

5) (10+3i)/(20-12i)=(10+3i)(20+12i)/((20-12i)(20+12i))=(200+120i+60i+36i²)/(20²-(12i)²)=

=(200+180i-36)/(400+144)=(164+180i)/544=(41+45i)/136;

6) 5/(1+2i)=5*(1-2i)/((1+2i)(1-2i))=(5*(1-2i)/(1²-(2i)²)=(5*(1-2i)/(1+4)=(5*(1-2i)/5=1-2i;

7) (2i-3)/(1+i)=(2i-3)(1-i)/((1+i)(1-i))=(2i-3-3i-2i²)/(1²-i²)=(-3+2-i)/(1+1)=(-1-i)/2=-(1+i)/2;

8) (5+3i)/(1+2i)=(5+3i)(1-2i)/((1+2i)(1-2i))=(5-10i+3i-6i²)/(1²-(2i)²)=(5-7i+6)/(1+4)=(11-7i)/5;

9) (1+2i)/(-2+i)=(1+2i)/(i-2)=(1+2i)(i+2)/((i-2)(i+2))=(i+2i²+2+4i)/(i²-4)=(5i-2+2)/(-1-4)=5i/(-5)=-i.

10)

1. (2+i)/(2-i)=(2+i)(2+i)/((2+i)(2-i))=(2+i)²/(4-i²)=(3+4i+i²)/(4+1)=(4+4i-1)/5=(3+4i)/5;

2. (3+4i)(3+4i)/5=(3+4i)²/5=(9+24i+16i²)/5=(9+24i-16)=(-7+24i)/5;

3. (4-i)/(3+2i)=(4-i)(3-2i)/((3+2i)(3-2i))=(12-3i-8i+2i²)/(9-4i²)=(12-11i-2)/(9+4)=(10-11i)/13;

4. (-7+24i)/5+(10-11i)/13=(13*(-7+24i)+5*(10-11i))/65=(-91+312i+50-55i)/65=(257i-41)/65.