Question

$(4 \sqrt{a} - \frac{4a - 2 \sqrt{a} }{2 + \sqrt{a} } ) \div \frac{1}{2 + \sqrt{a} }$

Answer 1

$\tt\left(4\sqrt{a}-\cfrac{4a- 2\sqrt{a}}{2+\sqrt{a}}\right):\cfrac{1}{2+\sqrt{a}}= \cfrac{4\sqrt{a}(2+\sqrt{a})-(4a- 2\sqrt{a})}{2+\sqrt{a}}\right)\cdot\cfrac{2+\sqrt{a}}{1} = \\\\\\=8\sqrt{a}+4a-4a+ 2\sqrt{a}=10\sqrt{a}$