Question

(x-1)(x+2)=10 пожалуйста помогите

Answer 1

x²+2x-x-2=10

x²+x-12=0

D= 1+48=49

x1= (-1+7)/2= 3

x2= (-1-7)/2= -4

Answer 2

$\left(x-1\right)\left(x+2\right)=10\medskip\\x^2+x-2-10=0\medskip\\x^2+x-12=0\medskip\\\left(x-3\right)\left(x+4\right)=0\medskip\\\left[\begin{gathered}x=3\\x=-4\end{gathered}$

Ответ. $x\in\left\{3;-4\right\}$