Question

решите уровнение 5 клас 87:(4x+5)=3

Answer 1

$87 \div (4x + 5) = 3 \\ \frac{87}{4x + 5} = 3 \\ \\ 87 = 3(4x + 5) \\ 87 \div 3 = 3(4x + 5) \div 3 \\ 29 = 4 x+ 5 \\ - 4x = 5 - 29 \\ - 4x = - 24 \div - 4 \\ x = 6$