Question

задача алгебра 30 баллов

Answer 1

${a}^{ \frac{1}{2} } = \sqrt{a} = 9 \\ {b}^{ \frac{1}{2} } = \sqrt{b} = 4 \\ {a}^{ \frac{1}{4} } = \sqrt[4]{a} = 3 \\ {b}^{ \frac{1}{4} } = \sqrt[4]{b} = 2$

$\frac{ {a}^{ \frac{1}{2} } - {b}^{ \frac{1}{2} } }{ {a}^{ \frac{1}{4} } + {b}^{ \frac{1}{4} } } - \frac{ {a}^{ \frac{1}{2} } - 3 {a}^{ \frac{1}{4} } b ^{ \frac{1}{4} } }{ {a}^{ \frac{1}{4} } } = \\ = \frac{ {a}^{ \frac{1}{2} } - {b}^{ \frac{1}{2} } }{ {a}^{ \frac{1}{4} } + {b}^{ \frac{1}{4} } } - {a}^{ \frac{1}{4} } + 3 {b}^{ \frac{1}{4} } = \\ = \frac{9 - 4}{3 + 2} - 3 + 3 \times 2 = \\ = 1 - 3 + 6= 4$