Question

Помогите решить логорифмы

Log(5) 125
Log 1/3 27
0,5^log0,5 12
Log(6) 12+log(6) 3

Answer 1

$log_{5}(125) = log_{5}( {5}^{3} ) = 3 \\ log_{ \frac{1}{3} }(27) = log_{ \frac{1}{3} }( { \frac{1}{3} }^{ - 3} ) = - 3 \\ {0.5}^{ log_{0.5}(12) } = 12 \\ log_{6}(12) + log_{6}(3) = log_{6}(12 \times 3) = log_{6}(36) = 2$