Question

Выполните 3 задания на листе.

Answer 1

1)a)$\frac{3b}{2c}$

б)$\frac{2}{b-9}$

в)$\frac{7(x-y)}{(x-y)(x+y)}=\frac{7}{x+y}$

2)а)$\frac{(3b+7)b}{3b*b}-\frac{3*b^2}{3*b^2}=\frac{3b^2+7b-3b^2}{3b^2}=\frac{7}{3b}$

б)$\frac{4p-q}{(4p+q)(4p-q)}-\frac{4p+q}{(4p-q)(4p+q)}=\frac{4p-q-4p-q}{16p^2-q^2}=\frac{-2q}{16p^2-q^2}=\frac{2q}{q^2-16p^2}$

в)$\frac{5-4y}{y(y-6)}+\frac{4y}{y(y-6)}=\frac{5-4y+4y}{y^2-6y}=\frac{5}{y^2-6y}$

3)$\frac{12p-q}{4p}-\frac{3p*4p}{4p}}=\frac{12p-q-12p}{4p}=\frac{-q}{4p}=\frac{-28}{-0,35*4}=20$

4)$\frac{4*(25-y^2)}{y*(25-y^2)}-\frac{2*y*(y+5)}{(y-5)y(y+5)}+\frac{y*(2y+10)}{y*(25-y^2)}=\frac{4(25-y^2)-2y^2-10y+2y^2+10y}{y(25-y^2)}=\frac{4}{y}$