Question

$\frac{(x-1)}{2}$ + $\frac{(x+1)}{3}$ ≥ 7

Answer 1

$\frac{(x-1)}{2}+\frac{(x+1)}{3}\geq7$

3(x-1)+2(x+1)≥42

x≥43/5

x ∈ [8,6;∞)